Option 3 : 60°

**Given: **

∠PQR = 50°

∠PRS = 130°

**Concept:**

Sum of all angles on a straight line is 180°

**Calculation:**

∠PRS + ∠PRQ = 180°

130° + ∠PRQ = 180°

∠PRQ = 180° - 130° = 50°

ΔPQR

∠PRQ + ∠RPQ + ∠QRP = 180°

50° + ∠RPQ + 50° = 180°

∠RPQ = 180° - 100° = 80°

∠RPQ = ∠x = 80°

∠PRQ = ∠y = 50°

2(x - y) = 2(80° - 50°) = 2 × 30° = 60°

2(x - y) = 60°

The correct option is 3 i.e. 60°.

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